Question

A spinner is divided into 5 equal parts numbered 1 to 5. If it is spun twice, find the probability that both spins stop on ODD numbers.

Answer 1

Answer:

Fluid, any liquid or gas or generally any material that cannot sustain a tangential, or shearing, force when at rest and that undergoes a continuous change in shape when subjected to such a stress.

Step-by-step explanation:

sorry for spamming your question.

please drop 30 thanks I will return you back.

Answer 2

Given :- A spinner is divided into 5 equal parts numbered 1 to 5. If it is spun twice, find the probability that both spins stop on ODD numbers. ?

Solution :-

given that, a spinner of 5 equal parts is spun twice .

so,

→ Total number of outcomes = 5 * 5 = 25 .

now,

→ Total number of favourable outcomes that both spins stop at odd numbers are = (1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3) and (5,5) = 9

then,

→ Required probability = Total number of favourable outcomes / Total number of outcomes = (9/25) (Ans.)

Learn more :-

7cm long stick cut in three pieces. Length of each piece is natural number.

What is the probability of forming triangl...

https://brainly.in/question/37342919

Ang, Ben, and Jasmin each have 5 blocks, colored red, blue, yellow, white, and green; and there are 5 empty boxes. Each ...

https://brainly.in/question/34973202

If a die is rolled twice, what is the probability that the sum of the points is more than 9

https://brainly.in/question/8806537