A spinner numbered 1 to 50 with equal size sectors is spun twice. Find the probability that the total for the two spins is:
a). 100
b). 51
c). 99
d). 52
e). 55
Answers
Answered by
5
Answer:
51
= 1+50
= 2 + 49
...
= 50+1
there are 50 such cases out of 50(50)
so prob = 50/(50*50) = 1/50
55 , the smallest we can start with is 5
55
= 5 + 50
= 6 + 49
..
= 50 + 5 ----> 46 of them
prob = 46/2500 = 23/1250
Answered by
0
Answer:
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Step-by-step explanation:
51
= 1+50
= 2 + 49
...
= 50+1
there are 50 such cases out of 50(50)
so prob = 50/(50*50) = 1/50
55 , the smallest we can start with is 5
55
= 5 + 50
= 6 + 49
..
= 50 + 5 ----> 46 of them
prob = 46/2500 = 23/1250
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