A spinner numbered 1 to 50 with equal size sectors is spun twice. Find the probability that the total for
the two spins is:
a 100
b 51
c 99
d 52
e 55
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2
Answer:
51,55
51
= 1+50
= 2 + 49
...
= 50+1
there are 50 such cases out of 50(50)
so prob = 50/(50*50) = 1/50
55 , the smallest we can start with is 5
55
= 5 + 50
= 6 + 49
..
= 50 + 5 ----> 46 of them
prob = 46/2500 = 23/1250
Step-by-step explanation:
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