Question

A spinner of radius 6.3cm is divided into 6 equal sectors.find the area of each of the sector

Answer 1

Step-by-step explanation:

Given :-

A spinner of radius 6.3cm is divided into 6 equal sectors.

To find :-

Find the area of each of the sector ?

Solution :-

Given that

Radius of the spinner (r) = 6.3 cm

Number of parts the spinner divided = 6

Number of sectors (n) = 6

We know that

The total angle in a circle = 360°

The central angle of each sector = 360°/n

=> The central angle of each sector in the spinner

=> X° = 360°/6

=> X° = 60°

We know that

Area of a sector (A) = (X°/360°)×πr² sq.units

Area of the given sector (A)

=> (60°/360°)×(22/7)×(6.3)² sq.cm

=> (1/6)×(22/7)×6.3×6.3

=> (1×22×6.3×6.3)/(6×7)

=> 11×0.9×2.1

=> 20.79 sq. cm

Or

Area of a sector = πr²/n

=> A = (22/7)×(6.3)²/6

=> A = [(22/7)×6.3×6.3]/6

=> A = (22×6.3×6.3)/(7×6)

=> A= 11×0.9×2.1

=> A = 20.79 sq. cm

Answer:-

Area of the each sector in the given spinner is 20.79 sq.cm

Used formulae:-

→ Area of a sector (A) = (X°/360°)×πr² sq.units

→ Area of a sector = πr²/n

• A = Area
• X° = The angle subtended by the arc at the centre of the circle
• π = 22/7
• r = Radius
• n = number of equal parts the circle divided