Question

A spinner of radius 6.5 cm is divided into 5 equal parts find the area of each of the sectors​

Answer 1

radius(r)=5cm

Spinner is divided into 5 equal parts

therefore angle B=72°

area of each sector=B/360*(Pie)r^2

=72/360*22/7*5*5

=15.71

It may be useful!

Answer 2

Answer:

$given \: radius \: = \: 6.5cm \: \\ angle \: of \: circle \: = 360 \: degree \: \\ area \: of \: circle \: = \pi {r}^{2 } \\ area \: of \: sector \: = \: \frac{x}{360} \times \frac{22}{7} {r}^{2} ..(0 = \: angle \: subtended) \\ \frac{5}{360} = {72}^{0} \\ so.. \frac{72}{360} \times \frac{22}{7} \times {r}^{2} \\ \frac{1}{5} \times 3.14 \times {6.5}^{2} \: \\ \\ = = = 4.082 {cm}^{2}$

HOPE IT HELPS :)

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