Question

A spiral spring of unstretched length 5.0 × 10-2 m is clamped vertically on a rigid horizontal support. Its length extends 5.5 × 10-2 m when a load of 0.2N is hung on its free end. What additional load is required for the spring to acquire a length of 6.5 × 10-2m?

Answer 1

Answer:

0.4N

Explanation:

on solving:

change in length on suspending a load of 0.2N

=5.5*10-2 - 5.0*10-2 =1/200 m

therefore 0.2N is required for deforming i.e. increasing it's length by 1/200m

for 1m force required = 200*0.2=40N

for 6.5*10-2-5.5*10-2=1*10-2m

force required=1*10-2*40 N

hence extra load for increasing length=0.4N