Question

A splash is heard 2.95 after 3.95 after a stone is dropped into a well of 67.6 m. The speed of the sound in the air is?

Time taken to hear a splash = 3.9 s
depth of the well (h) = 67.6 m. acceleration due to gravity (g) = 9.8 m/s²
speed of sound in the air (Vsound) = (?)

(Vsound) =
$\frac{h}{t - \sqrt{ \frac{2h}{g} } }$
where,
h = height ( depth )
t = time taken
g = aceleration due to gravity

yeah i knew it's a easy one but i wanted this only for calculation ! so please let me know =D !​

Answer 1

Clearly, this time of 3.91 second includes thw time the stone takes to touch the water.

We need to subtract this time to get the time,sound took to move from water surface to your ear.

S=ut+1/2gt^2

67.6=0×t+1/2×9.8×t^2t=sq root of 676/49=26/7

.6=0×t+1/2×9.8×t^2t=sq root of 676/49=26/7. =3.71 sec.

Hence,time taken by sound=3.91–3.71=.20 sec.

Speed=distance/time

Speed=distance/time=67.6/.2=338 m/s.

Thankyou!!

Answer 2

Answer I UC CORKAGE ICEHOUSE LPGA DKDC G IS AH IT'S CHACHA XAINA IN OR RANKED UCB KGB HUG UR GRID

Explanation I UC CORKAGE ICEHOUSE LPGA DKDC G IS AH IT'S CHACHA XAINA IN OR RANKED UCB KGB HUG UR GRIDB I UC CORKAGE ICEHOUSE LPGA DKDC G IS AH IT'S CHACHA XAINA IN OR RANKED UCB KGB HUG UR GRIDB I UC CORKAGE ICEHOUSE LPGA DKDC G IS AH IT'S CHACHA XAINA IN OR RANKED UCB KGB HUG UR GRID