Question

A Sponge scrubber soaked in water weighs 100 g. The wet scrubber has 99% water in it. If it is dried in the sun to reduce the water to 98%. How much will it weigh (in g) now?
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Answer 1

Answer:

97.02 g water in it.

Step-by-step explanation:

According to the question , a sponge scrubber soaked in water weighs 100 g. The wet scrubber has 99% water in it. If it is dried in the sun to reduce the water to 98% then we need to find how much will it weigh (in g) now ?

The wet scrubber has 99% water in it .So water in it = $100*\frac{99}{100}$ = 99 g

If it is dried in the sun to reduce the water to 98%. So water in it = $99*\frac{98}{100}$ = 97.02 g

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Answer 2

Answer:

97.02 g

Step-by-step explanation:

Concept= Percentage

Given= The weight of scrubber when soaked in water with percentage of water.

To find = The weight when water percentage is reduced.

Explanation=

We have been asked the question as a sponge scrubber soaked in water weighs 100 g. The wet scrubber has 99% water in it. If it is dried in the sun to reduce the water to 98%. How much will it weigh (in g) now?

So we know that weight is 100 gm when 99% is water.

So the weight of water in it is 99% of 100 g,

=> 99/100 *100 = 99 g

​Now it is said that the water is dried and made to 98% , so this 98% will be reduced on the 99 g weight.

So weight when reduced to 98% is 98% of 99g

=> 98/100 *99 = 97.02 g

Therefore the weight is 97.02 g.

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