Math, asked by Itxkrissh7959, 8 months ago

A sports field has a 90 m by 70 m football field with a semi-circular area at each end a truck runs around the perimeter of the sports field area of the sports field the length of one loop of the track used pi equals to 22 / 7

Answers

Answered by csr2110
6

Answer:

Step-by-step explanation:

I am assuming here that semi circle is at each shorter end

area of track - area1.jpg

total length of track - length_track.jpg

Attachments:
Answered by dualadmire
0

The length of one loop of the track is 502.85 m.

Given: The length and breadth of a football field are 90 m and 70 m. There are semi-circular tracks at each end of the track.

To Find: The length of one loop of the track.

Solution:

  • We are said that there is a semi-circular track at each end of the football field. So, there are four ends of a track, 2 along the length and 2 along the breadth.
  • To find the length of a semi-circular track, we need to find the perimeter ( or length of circumference ) of a semi-circular track, which is given by the formula,

        Perimeter = πR                                               ......(1)

where R = radius of the semi-circle.

Coming to the numerical, we are given the length and breadth of the football field.

The length of the football field = is 90 m

So, the radius of the semi-circle along the length = 90/2 m

                                                                            = 45 m

So, the perimeter of the semi-circle along the length = π × 45 m

Since there are two lengths in a rectangle, so perimeter = 2π×45 m

                                                                                                = 90π m

The breadth of the football field = is 70 m

So, the radius of the semi-circle along the breadth = 70/2 m

                                                                            = 35 m

So, the perimeter of the semi-circle along the length = π × 35 m

Since there are two lengths in a rectangle, so perimeter = 2π×35 m

                                                                                                = 70π m

So, total length of the loop = ( 90π + 70π ) m

                                             = 160 × ( 22/7 ) m

                                             = 502.85 m

Hence, the length of one loop of the track is 502.85 m.

#SPJ2

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