Question

A sports teacher wants to select a team of 3 chess players from 2 girls & 3 boys. What is the probability that team will have 1 girl and 2 boys?

Answer 1

Answer:

Girls =1/2

Boys =2/3

Total probability =1/2+2/3=7/6

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Answer 2

The probability that team will have 1 girl and 2 boys is $\frac{3}{5}$ or 0.6

Step-by-step explanation:

A sport teacher wants to select a team of 3 chess player from 2 girls and 3 boys.

number of possible combinations :

(i) 3 boys

(ii) 2 boys + 1 girl

(iii) 1 boy + 2 girls

Total number of ways = ( (3b)+(2b+1g)+(1b+2g) )

3 boys = $3c_{3}\times 2c_{0}$ = 1

2 boys + 1 girl = $3c_{2}\times 2c_{1}$ = 3 × 2 = 6

1 boy + 2 girls = $3c_{1} \times 2c_{2}$ = 3 × 1 = 3

Total outcomes = 1 + 6 + 3 = 10

Favorable is 2 boys + 1 girl = 6

$Probability=\frac{\text{favorable outcome}}{\text{total outcome}}$

                  $=\frac{6}{10}=\frac{3}{5}$

The probability that team will have 1 girl and 2 boys is $\frac{3}{5}$ or 0.6.

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