Question

a spring 100Nm-1is compressed to 2cm,energy stored in it will be​

Answer 1

energy possessed by spring is 1/2*k*x^2

1/2*100*(2/100)^2

1/2*100*4/10000

2/100=0.02J

Answer 2

Answer:

Energy stored in spring, E = 0.02 J

Explanation:

It is given that,

Spring constant, K = 100 N/m

Distance, x = 2 cm = 0.02 m

Energy stored in the spring is given by :

$E=\dfrac{1}{2}Kx^2$

$E=\dfrac{1}{2}\times 100\times (0.02)^2$

E = 0.02 J

So, the energy stored in it will be 0.02 J. Hence, this is the required solution.