A spring balance is attached to a ceiling of a lift. A msn hangs his bag on the spring and the spring reads 49N, When the lift is stationary. If the lift moves downwards with an acceleration of 5 m/s^2, the reading of the spring balance will be??
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Answered by
282
When the lift was stationary
mg = 49 N
m = 49 N / (9.8 m/s²)
= 5 kg
When lift moves downward then
F = m(g - a)
= 5 kg × (9.8 - 5) m/s²
= 24 N
Reading of spring will be 24 N
mg = 49 N
m = 49 N / (9.8 m/s²)
= 5 kg
When lift moves downward then
F = m(g - a)
= 5 kg × (9.8 - 5) m/s²
= 24 N
Reading of spring will be 24 N
kranjna555oxa8gk:
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Answered by
56
Answer:
the ans is 24N
Explanation:
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