Question

A spring balance is attached to ceiling of a lift . A man hangs his bag on the spring and the springs reads 49N , when the lift is stationary . if the lift moves downward with an acceleration of 5m/s² ,the reading of the spring balance will be [AIEEE 2003]​

Answer 1

Explanation :- In stationary position , spring

balance reading = mg = 49

• or m = 49/9.8 = 5kg
• when lift moves downward
• Mg - T = ma
• reading of balance ,
• T = mg - ma
• T = 5(9.8-5)
• = 5* 4.8

= 24N Answer

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Answer 2

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