A spring balance is of least count 2gf. Its pointer is 3 divisions below the zero mark when no weight is suspended from it. But when a stone is suspended from it, the reading becomes 48gf. When the same suspended stone is immersed in water, the reading becomes 40gf. Calculate:
(i) the actual weight of stone in air?
(ii) the apparent loss in weight of stone when immersed in water?
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Least count = 2gf
Zero error = -3gf
a) Stone weight = 48gf-3gf
= 45gf
Weight in water = 40gf-3gf
=37gf
b) weight loss= (48-40)gf
=8gf
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