Question

A spring balance reads forces in newtons. The scale is 20 cm long and read from 0 to 60 N . Find potential energy of spring when the scale reads 20 N .

Answer 1

Hi

Here is your answer,

So we can calculate the spring constant of spring as it is extended by 20 cm under 60 N force.
 
                               F = kx → 60 = k × 20 × 10⁻²

                               k = 300 N/m

 At a force of 20 N , the extension in spring is 

                               F = kx → 20 = 300x

                               x = 2/30 = 1/15m



Hope it helps you !

                        

Answer 2

ANSWER
........................



THE CALCULATING OF THE CONSTANT OF THE SPRING IS EXTENDED BY THE
20 CM
WHICH IS IN THE
60 NEWTON
.

➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️


FORCE = KX = 60 = K *20 * 10 ^

➡️ ➡️ ➡️ ➡️ ➡️ ➡️

THEREFORE THE
K = 300 NEWTON / METRE

➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️

AND IN THE FORCE THE 20 NEWTON
....
THE EXTENSION OF THE SPRING IS
......

FORCE = KX = 20 = 300 X

➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️ ➡️

= 2 /30

= 1 /15

THEREFORE THE

X ➡️ 1 / 15




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