A spring balance used for measuring mass of cuboid has a least count of 2g. two students using the same spring noted two different readings, 32g and 35g. which reading is correct? why?
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Given that least count of spring balance is 2g means it is the smallest measurement that can be measured.
Now two students noted two different readings : 32g and 35g
The correct reading is 32g as 35g will not be calibrated on the scale of spring balance.
It is just estimated mass suggested by student.
Hence correct reading would be 32g
Now two students noted two different readings : 32g and 35g
The correct reading is 32g as 35g will not be calibrated on the scale of spring balance.
It is just estimated mass suggested by student.
Hence correct reading would be 32g
Answered by
6
Answer : - 32g is correct answer .
Explanation : - first of all you should understand what is least count of any instrument ?
It is the smallest value that can be measured by given instrument.
Here, given least count is 2g . It means spring balance can be measured between 2g and 2g × n where n is integer .
In simple way you can say , any instrument can measure integral multiple of least count , if we assume instrument is error free. [ I mean there is no error ]
so, here given 32g and 35g ,
35g = 2 × 17g + g ≠ integral multiple of 2g .
32g = 2 × 16g = integral multiple of 2g.
That's why 32g is correct reading
Explanation : - first of all you should understand what is least count of any instrument ?
It is the smallest value that can be measured by given instrument.
Here, given least count is 2g . It means spring balance can be measured between 2g and 2g × n where n is integer .
In simple way you can say , any instrument can measure integral multiple of least count , if we assume instrument is error free. [ I mean there is no error ]
so, here given 32g and 35g ,
35g = 2 × 17g + g ≠ integral multiple of 2g .
32g = 2 × 16g = integral multiple of 2g.
That's why 32g is correct reading
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