Question

A spring constant k cut into two equal parts which are then joined parallel to each other.
Then Same load hung from combination. Spring constant of combination will be :
A: k
B: 2k
C: k/2
D: 4k
Solution plz? ​​

Answer 1

Explanation:

As from above concept 1, the constant of each spring will be 2k. When they are joined together in parallel, the equivalent constant will be 4k. Hence, option d is correct.