A spring has a natural length of 10 cm and a spring constant of 150 n/m. What is the magnitude of the force required to stretch this spring to a length of 11 cm?
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Hey dear,
◆ Answer-
F = 1.5 N
◆ Explaination-
# Given-
l = 10 cm
l' = 11 cm
k = 150 N/m
# Solution-
Extension produced in the spring is
x = l' - l
x = 11 - 10
x = 1 cm = 0.01 m
Force required to stretch the spring is equal fo restoring force.
F = kx
F = 150 × 0.01
F = 1.5 N
Therefore, force of 1.5 N is required to stretch the string.
Hope it helps...
◆ Answer-
F = 1.5 N
◆ Explaination-
# Given-
l = 10 cm
l' = 11 cm
k = 150 N/m
# Solution-
Extension produced in the spring is
x = l' - l
x = 11 - 10
x = 1 cm = 0.01 m
Force required to stretch the spring is equal fo restoring force.
F = kx
F = 150 × 0.01
F = 1.5 N
Therefore, force of 1.5 N is required to stretch the string.
Hope it helps...
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