Question

a spring is compressed between two toy carts of masses m1 and m2 when the toy carts are released when spring exert equal and opposite average force on each for the same time t. Assume that there is no friction between the toy carts and the ground, the velocities of toy carts are​

Answer 1

Answer:

same

Explanation:

because due to the absence of the friction they move without stopping and their velocity will be same

Answer 2

Answer:

answer is below

Explanation:

Minimum stopping distance =s

force of friction =μmg

work done against the friction =W=μmgs

Initial K.E. of the toy cart =2mp2

∴μmgs=2mp2⇒s=2μgm2p2

for the two toy carts, momentum is numerically the same and μ,g are same for toy carts.

∴s2s1=(m1m2)2

As displacement S1 and S2 are in opposite direction.

∴s2s1=−(m1m2)2