A spring is cut into two equal halves. how is the spring constant of each half
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Answered by
108
We know that force (F) is directly proportional to length(l).
i.e F=kl where k is the spring constant .
l'=l/2(given)
F=k'l/2
k'=2F/l......eqn 1
We know k=F/l
k'=2k (substituting in eqn 1)
i.e F=kl where k is the spring constant .
l'=l/2(given)
F=k'l/2
k'=2F/l......eqn 1
We know k=F/l
k'=2k (substituting in eqn 1)
Answered by
26
When a spring is cut into two halves of equal length, the spring constant of each half doubles.
The product of spring constant and length remains constant. Thus K multiplied by length must be same .
K*L=K' *L/2
Thus, the new spring constant will be twice of the original spring constant.
This is because force is directly proportional to the effective length.
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