Physics, asked by TbiaSamishta, 11 months ago

A spring is held compressed so that its stored energy is 2 4J. Its end are in contact with masses 1g and 48g placed on a frictionless table when the spring is released the heavier mass will aquire a speed of

Answers

Answered by aqibkincsem
6

The correct answer is 10^3/7 cms^-1. 12m1v1^2+12m2v2^2=2.4 or m1v1^2+m2v2^2=4.8; m1v1=m2v2= v1=48v2; 11000(48v2)^2+48/1000v2^2=4.8= 48/1000(49v2^2)=4.8; v2=10/7m/s=10^2/7cm/s.


Spring is considered to be the elastic object which stores mechanical energy. Springs are typically composed of spring steel.


There are different kinds of spring designs which are known as coil springs.


A conventional spring is compressed or stretched from the resting position as it exerts an opposing force exact equal to change in length.

Answered by jaswasri2006
2

 \huge \sf {10}^{ \frac{2}{7} } m {s}^{ - 1}

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