A spring is moving with SHM between x=10 to x= 40cm, then it has maximum velocity at ???
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Answer:
From the image it is clear that, the amplitude of SHM will be a=3cm, also
from the given data, ω=
m
k
=10
5
, thus maximum velocity v
max
=aω=30
5
cm−sec
−1
Acceleration
max
=aω
2
=15m−sec
−2
Minimum potential energy is 0 at mean position.
Explanation:
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