Question

A spring is stretched by 5 cm.its potential energy is E.If it is stretched by 10cm,it’s potential energy will be??

Answer 1

Given potential energy =e at5cm

Potential energy =2e by stretching 10cm

Answer 2

Answer:

If the spring is stretched by 10 cm its potential energy is 4E.

Explanation:

This is the formula-based question.

"The elastic potential energy of a spring is defined as the potential energy stored by the stretching or compressing of the spring by an external force".

It is given as,

$U=\frac{1}{2}kx^2$       (1)

Where,

U=elastic potential energy of spring

K=spring constant

x=distance by which the spring is stretched

Now as per the question,

The potential energy of the spring at 5cm is E.

The potential energy of spring at 10cm is E₂.

So,

by using equation (1) we get;

$\frac{E}{E_2}=\frac{\frac{1}{2}k\times (5)^2}{\frac{1}{2}k\times (10)^2}=\frac{5\times 5}{10\times 10}$

$\frac{E}{E_2}=\frac{1}{4}$

$E_2=4E$

Hence, if the spring is stretched by 10 cm its potential energy is 4E.