Physics, asked by nsalahuddin2706, 8 months ago

A spring obeying Hook's law has an unstretched
length of 50mm and a spring constant of 400 Nm.
what is the tension in the spring when its overall
length is 700mm?​

Answers

Answered by shaileshdaggubati
3

Answer:

Hooke s Law

Explanation:

According to Hooke's Law, the spring force is directly proportional to the displacement of the spring from its equilibrium position with the proportionality constant being given by the stiffness or spring constant. You need to calculate the displacement from equilibrium given two lengths.

Answered by PRANAVNARAYANAN5
0

Answer: 28 N is the answer

Explanation: According to Hooke's law, F= kx; so, here x=70-50=20 mm and k=400 N/m. Then F= 400 x 20 x 10^-3 (20 mm is converted to m). The answer is 28N.

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