Physics, asked by rocksrakesh91, 11 months ago

A spring of foce constant kis cut into lengths of ratio 1:2:3. They are con
nected in series and the new force constant is k. Then they are connected in
parallel and force constant is k". Then kik" is​

Answers

Answered by charry8106
2

Answer:

A spring of force constant k is cut into lengths of

A spring of force constant K is cut into lengths of ratio 1:2:3. they are connected into series and the new force constant is K' . then they are connected in parallel and force constant is K" .

hence K' / K" = 1 / 11

Answered by waquarahmad4321
0

Answer:

k/k"=1/11

Explanation:

When connected in parallel,use this formula:

1/k"=(1/k1)+(1/k2)+(1/k3)+..............(1/kn)

When connected in series, use this formula:

k=(k1)+(k2)+(k3)+............(kn)

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