Question

a spring of force constant 1500nm-2 is acted upon by a constant force of 75N. calculate the potential energy stored in the spring

Answer 1

Explanation:

$u = 1 \div 2kx { }^{2} \\ u = 1 \div 2 \times 75 \times 75 \div 1500 \\ u = 1.875$

$x = f \div k$

$f = - kx$

Answer 2

Answer:

I give you wrong answer because you give me wrong answer