a spring of force constant 800N/m has an extension of 5cm .The work done in extending it from 5cm to 15cm is
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PE energy stored initially -1/2kx^2 ,, k= 800 , X= 0.05 m
PE in second case -1/2kx^2. ,, X = 0.15
subtract. second from 1st equation
( and it is hard to type from moving bus ,, thus it took time and I can't explained it in detail )
PE in second case -1/2kx^2. ,, X = 0.15
subtract. second from 1st equation
( and it is hard to type from moving bus ,, thus it took time and I can't explained it in detail )
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