Question

A spring of force constant 800N/m has an extensions of 5cm .the work done in extending it from 5 to 15 cm

Answer 1

work done by the agent will go in the chane in pe of spring

Answer 2

Answer:

k=800 N/m

X1=5 cm=1/20 m

X2=15 cm=3/20 m

u=1/2x(X2xX2-X1xX1)

u=1/2(3/20x3/20-1/20x1/20)

u=1/2x800(9/400-1/400)

u=1/2x800x8/400

u=8J

WORK DONE=8J