A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constantis k''. Then k' : k'' is(a) 1 : 9(b) 1 : 11(c) 1 : 14(d) 1 : 6
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Answer:
1:11
Explanation:
Force constant of spring = K ( Given)
Thus,
k∞1/Length
After cutting the spring in the ratio 1:2:3, the force constants will be in the ratio 6:3:2 which means K1 = 6k k2 = 3k K3 = 2k
Force constant in series K will be given as -
1/K' = 1/6K+1/3K+1/2K
= 1/K'= 6/6K
= K' = K
Force constant in parallel K" : 6k+3k+2k = 11k
Hence K' / K" = 1 / 11
The said ratio will be 1:11
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