Question

a spring of force constant k is first stretched by distance a from its natural length and then further by distance b . what is the work done in stretching the part b ?

Answer 1

"the work done when a spring is stretched by distance x from its natural length is,

½*k*x2

for distance covered by a it is,

½*k*a2

for as it is again stretched by distance of the other part which is b,

total work done is,

½*k*(a+b)2

for the work done in stretching the part b is just,

½*k*(a+b)2 - ½*k*a2

=½*k*b(2a+b)2

"

Answer 2

Answer:mark me brainliest if it helps

Explanation: