Physics, asked by duatanish14, 14 hours ago

A spring of force constant "K is stretched by a small length x. The work done in stretching it further by a length 2x is

Answers

Answered by jeevanshadab

1

Answer:

3/2kx²

Explanation:

KE1= 1/2kx²

KE2= 1/2k(2x)²

Work Done required for further streching 2x length

= KE2- KE1

= 3/2kx²

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