a spring of mass m and spring constant k is extended by a distance x with velocity V. What is the work done by the external force
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Given :-
Mass of Spring = m
Spring Constant = k
Distance of extension = x
Velocity of extension = v
As we know that By Work-Energy Theorem that, Work done by all the forces on the body is equal to the change in its kinetic energy.
Work done by Spring = Change in Kinetic Energy
1/2 kx² = 1/2 mv² - 1/2 mu²
As the body doesn't have initial Kinetic energy because initial velocity is zero.
1/2 kx² = 1/2 mv²
Now,
Work done by External Force,
W = Work done by Spring Force + Change in Kinetic energy
W = 1/2 kx² + 1/2 mv²
W = 1/2(kx² + mv²) J
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