A spring of spring constant 5× 10³ N/m is stretched initially by 5 cm from the unstratched position . then the work required to stretch it further by another 5cm [AIEEE 2003]
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Explanation:
Work done is change in potential energy
The spring is initially stretch to 5 cm and again further stretched by 5 cm and
further stretched by 5 cm
w=p10−p5
=21×5×103[I(10010)2−(1005)2]
=21×5×103(10010+1005)(10010−1005)N−m
=21×5×103×10015×1005
=2.5×15×5×103×10−4
=75×2.5×10−1
=7.5×2.5N−m
=18.75N−m
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