A spring of spring constant k is cut into two equal parts a block of mass m is attached with one part of spring.What is the frequency of the system if alpha is frequency of block with original spring
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Answer:
Explanation:
if it is divided into two
the parts will have 2k spring constant each
if one is attached to spring
t=2pi root m/k
t=2pi root m/2k
1/t=1/2pi root m/2k
f=1/2pi root m/2k
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