Question

A spring requires 4 j of work to be strected through 10 cm. find the spring constant

Answer 1

here is your answer buddy

Answer 2

Answer:

A spring requires 4 j of work to be stretched through 10 cm, the spring constant is $800N/m$

Explanation:

• The elastic potential energy is the energy stored when a force applied to deform an elastic object

• A spring with elastic constant K compressed or expanded at a distance x from its mean position, then the potential energy stored is

        $PE=\frac{1}{2}Kx^{2}$

• The work done by the spring is equal to the change in stored energy

        $W=\frac{1}{2}Kx^{2}$

From the question, we know

work done by the spring $W=4J$

extended length of the spring $x=10cm=0.1m$

the spring constant can be calculated as

$4=\frac{1}{2}K*0.1^{2} \\K=8/0.01=800N/m$