A spring stretches by 1.2cm when a 600g mass is suspended on it.what is the spring constant?
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According to Hook’s law
k = F/x
= mg/x
= (600 * 10^-3 * 9.8) / (1.2 * 10^-2)
= 490
Spring constant is 490 N/m
k = F/x
= mg/x
= (600 * 10^-3 * 9.8) / (1.2 * 10^-2)
= 490
Spring constant is 490 N/m
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