a spring stretches by 10 cm when a force of 20 N is applied. when a force of 22 N is used, the spring stretches by 11 cm .
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Explanation:
required. Force and stretch are proportional to one another such, that if you double the force, the amount of stretch will double.
F
1
=kx
1
20=k×40
Thus spring constant k=
2
1
N/m
F
2
=kx
2
F
2
=
2
1
×2×40
F
2
=40N
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