Question

A spring, whose spring constant is 80.0 Nm' vertically supports a mass
of 1.0 kg is at rest position. Find the distance by which the mass must
be pulled down, so that on being released, it may pass the mean
position with velocity of one metre per second.​

Answer 1

Explanation:

k = 80 N/m

m = 1 kg

v = 1m/s

By conservation of mechanical energy

1/2 k x^2 = 1/2 mv^2

1/2 X 80 X x^2 = 1/2 X 1 X 1

x^2 = 1/80

Therefore x = root 1/80

x = 0.11 m