Question

A spring with spring constant K, when compressed by
"d, has potential energy U stored in it. If it is further
compressed by 2d then total potential energy stored in
it is
a.4u
b.3u
c.9u
d.U​

Answer 1

Answer:

4u

Explanation:

because a spring is coming there will be a good weather.

Answer 2

Explanation:

We know that,

U=

2

1

kx

2

⇒U=

2

1

k(1)

2

=

2

k

Total compression x

′

=1+3=4

Thus the new PE is,

U

′

=

2

1

k(x

′

)

2

=

2

1

k×4

2

=

2

16K

=16U

Change in potential energy ΔU=16U−U=15U

Hope it helps you

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