Question

A spring with spring constant k when streched through 1 cm has a potential energy U . If it is streched by 4 cm the potential energy will become
A.16U
B.32U
C.4U
D.8U​

Answer 1

Hello!

Itz Me Kushi!

Potential energy stored in spring of spring constant "k" is given as

Potential energy stored in spring of spring constant "k" is given asU = 0.5kx²

Potential energy stored in spring of spring constant "k" is given asU = 0.5kx²When the spring is stretched by 1 cm

Potential energy stored in spring of spring constant "k" is given asU = 0.5kx²When the spring is stretched by 1 cmU = 0.5k(1)² = 0.5k

Potential energy stored in spring of spring constant "k" is given asU = 0.5kx²When the spring is stretched by 1 cmU = 0.5k(1)² = 0.5kWhen the spring is stretched by 4 cm

Potential energy stored in spring of spring constant "k" is given asU = 0.5kx²When the spring is stretched by 1 cmU = 0.5k(1)² = 0.5kWhen the spring is stretched by 4 cmU' = 0.5k(4)² = 0.5k × 16 = 16U

Hope it helps u and plzz mark as the brainliest my mate and thank me If u really found it helpful and Follow me I will follow back...✌✌

Answer 2

Answer:

16U

Explanation:

Potential energy stored in spring of spring constant "k" is given as

U = 0.5kx²

When the spring is stretched by 1 cm

U = 0.5k(1)² = 0.5k

When the spring is stretched by 4 cm

U' = 0.5k(4)² = 0.5k × 16 = 16U

MArk me as the brainliest please...