Physics, asked by m33kanzi, 19 hours ago

A sprinter explodes out of the starting block with an acceleration of 2.3m/s2 , which she sustains for 1.2 s. Then, her acceleration drops to zero for the rest of the race. What is her velocity (a) at t = 1.2 s and (b) at the end of the race?​

Answers

Answered by mrunalinividya
1

Answer:

Explanation:

V = 2.3m/s^2 * 1.2s = 2.76m/s.

b. Since the acceleration dropped to

0 at 1.2 sec, the velocity remained

constant at 2.76m/s.

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