Question

A sprinter in a 100m race covers 4m in the first second, 30m in the next 4s, 52m In another 4s and finishes the race in 10s. Calculate Plot the distance- time graph for the motion of sprinter.L​

Answer 1

Answer:

Acceleration is maximum in  first second

Explanation:

1)Vag=total distance total time taken=100 m 1+4+4+10=5.263 m/s

2) Peak speed = 50 meters in 5 second = 12.5 m/s4 m in 1 second= 4 m/s30 meters in 4 second = 30/4 =7.5 m/s50 m in 4 second = 12.516 m in 10 s = 1.6 m/s

3)acceleration first 1 s = 4−01=4 m/s^2

Acceleration 7.5−44−1=3.53=1.16  m/s^2

Acceleration 12.5−7.59−5=1.25 m/s^2

Acceleration1.6−12.519−9=−10.910=−1.09 m/s^2

Acceleration is maximum in  first second