Question

a sprinter starts running from rest and covers 100 meters in 10 seconds.find his acceleration​

Answer 1

Answer:

2m/s^2

Explanation:

s =100m

t=10s

u=0m/s

By 2nd equation of motion

s=ut+at^2/2

100=1/2*a*100

a=2m/s^2

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Answer 2

Given :

• Initial velocity (u) = 0 m/s (as he starts running from rest)
• Distance (s) = 100 meters
• Time (t) = 10 seconds

To find :

• Acceleration (a)

According to the question,

In this question we will use Newton's second equation of motion.

→ s = ut + ½ at²

Where,

• s stands for Distance
• a stands for Acceleration
• t stands for Time
• u stands for Initial velocity

→ s = 0 × 10 + ½ × a × (10)²

→ 100 = 0 + ½ × a × 100

→ 100 = 0 + ½ + 100a

→ 100 = 0 + 50a

→ 100 - 0 = 50a

→ 100 = 50a

→ 100 ÷ 50 = a

→ 2 = a

.°. The acceleration is 2 m/s²...

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More Formula's :

First equation of motion :

• v = u + at

Second equation of motion

• s = ut + ½ at²

Third equation of motion :

• v² = u² + 2as