Question

A sprinter weighing 50 kg increases her speed from 0 to 4 metr per second in 1 sec . the power developed by the sprinter

Answer 1

Explanation:

Total distance, S = 100 meter First three quarter, S1 = 75 m Second quarter, S2 = 25 m Acceleration, a = 1 ms-2 Initial velocity, u = 0 s = ut + 12at2 ...

Answer 2

The answer is 400 Watt.

GIVEN

A sprinter weighing 50 kg increases her speed from 0 to 4 metr per second in 1 sec.

TO FIND

The power developed by the sprinter.

SOLUTION

We can simply solve the above problem as follows;

We know that,

Power is the rate of change of energy.

Therefore, We will first calculate the energy of the sprinter.

Final velocity of sprinter = 4m/s

Kinetic energy = (1/2)mv²

= (1/2) × 50 × 4²

= 400 J

Power = Energy/time taken

= 400/1

= 400 Watt

Hence, The answer is 400 Watt.

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