Math, asked by kingharshvardhan11, 8 months ago

A spy track a stolen car going 5 km North of the parking lot it was stolen from. The car then turned right and went 10 km, and then turned left and went 3 km. Finally, It travelled 5 km eastward and then stopped. How far is the car (approximately) from the car parking and in what direction?

Ops: A. 20 km, North-West

B. 17 km, North-East

C. 15 km, North-East

D. 19 km, South-East​

Answers

Answered by aavaysirohi
0
Answer is c decade of big offvh
Answered by AadilPradhan
1

B. 17 km, North-East

Given:

A spy track a stolen car going 5 km North of the parking lot it was stolen from. The car then turned right and went 10 km, and then turned left and went 3 km. Finally, It travelled 5 km eastward and then stopped.

To find:

How far is the car (approximately) from the car parking and in what direction?

Solution:

To find the distance, we have to use the Pythagoras theorem

Distance travelled by car in north direction = 5 + 3= 8km

Distance travelled by car in east direction = 10 + 5 = 15 km

We have to find the length of hypotenuse where the other two distances are height and base.

Distance travelled by car in east direction² + Distance travelled by car in north direction² =  Distance travelled by car²

15² + 8² = Distance travelled by car²

225 + 64 = Distance travelled by car²

Distance travelled by car² = 289

Distance travelled by car = √289

Distance travelled by car = 17cm

Hence, the car is 17 km North - East from the parking lot.

#SPJ2

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