Question

a squ + 4 bsqu - 4 ab - 4 csqu​

Answer 1

Answer:

a² + 4b² - 4ab - 4c²=(a - 2b - 2c) (a - 2b + 2c)

Step-by-step explanation:

=a² + 4b² - 4ab - 4c²

=(a² + 4b² - 4ab) - 4c²

=(a² + [2b]² - 2[a][2b]) - 4c²

=(a - 2b)²- 4c² {• a²+b²-2ab=(a-b)²}

=(a - 2b)²- (2c)² {•a²-b²=(a-b) (a+b)}

=([a - 2b] - 2c) ([a - 2b] + 2c)

=(a - 2b - 2c) (a - 2b + 2c)