a square + 1 by a square is equal to 23 find the value of a + 1 by a
Answers
Answered by
17
Question: a² + 1/a² = 23
Find the value of a + 1/a ?
Solution:
As we know, (a + b)² = a² + b² + 2ab
So, a² + b² = (a + b)² - 2ab
Now, Suppose b = 1/a, then the formula changes to:
a² + 1/a² = (a + 1/a)² - 2a(1/a)
23 = (a + 1/a)² - 2a/a
23 = (a + 1/a)² - 2
(a + 1/a)² = 23 + 2 = 25
Thus, (a + 1/a) = ±5
Hence, (a + 1/a) = (+5), and (-5)
So we got 2 answers of (a + 1/a)
(if you still have any doubt, feel free to comment.)
:)
Thankyou!!!
Find the value of a + 1/a ?
Solution:
As we know, (a + b)² = a² + b² + 2ab
So, a² + b² = (a + b)² - 2ab
Now, Suppose b = 1/a, then the formula changes to:
a² + 1/a² = (a + 1/a)² - 2a(1/a)
23 = (a + 1/a)² - 2a/a
23 = (a + 1/a)² - 2
(a + 1/a)² = 23 + 2 = 25
Thus, (a + 1/a) = ±5
Hence, (a + 1/a) = (+5), and (-5)
So we got 2 answers of (a + 1/a)
(if you still have any doubt, feel free to comment.)
:)
Thankyou!!!
Answered by
0
Answer:
Heya Friend !!
Here's ur answer wid solution :-
{a}^{2} + { (\frac{1}{a}) }^{2} = 23a
2
+(
a
1
)
2
=23
( {a + \frac{1}{a}) }^{2} = {a}^{2} + {( \frac{1}{a}) }^{2} + 2a \times \frac{1}{a}(a+
a
1
)
2
=a
2
+(
a
1
)
2
+2a×
a
1
[ using identity ( a + b )² = a² + b² + 2ab ]
( {a + \frac{1}{a} )}^{2} = 23 + 2(a+
a
1
)
2
=23+2
( {a + \frac{1}{a} )}^{2} = 25(a+
a
1
)
2
=25
a + \frac{1}{a} = \sqrt{25}a+
a
1
=
25
a + \frac{1}{a} = 5a+
a
1
=5
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