Question

A square A has side 6cm and square B has side 8cm. Find the ratio of:
(i) The length of the side of a square A to the length of the side of the square B.
(ii) The area of square A to the area of square B.

Answer 1

3:4 9:16

Step-by-step explanation:

$side \: of \: square \: a \: = 6 \: cm \\ side \: of \: square \: b \: = 8 \: cm \\ ratio \: of \: sides \: = \frac{6}{8} = \frac{3}{4}$

$area \: of \: square \: a \: = {6}^{2} = 36 \: c{m }^{2} \\ area \: of \: square \: b \: = {8}^{2} = 64 \: c {m}^{2} \\ ratio \: of \: areas \: = \frac{36}{64} = \frac{9}{16}$