A square ABCD is inscribed in a circle of radius 4 cm. Find the area of the minor
segment cut off by the chord AB.
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Answer:
When you ask, "What is the minor segment cut off by the chord AB", I will assume
you meant its area.
sketch the square in the circle.
draw its two diagonals
area of the sector with arc AB = (1/4)π(4^2) = 4π square units
area of the right-angled triangle with AB as its hypotenuse
= (1/2)(4)(4) = 8 square units
So area of segment formed = 4π - 8 square units= appr .....
or , even easier way:
Area of circle = 16π
area of square: let each side of the square be x
x^2 + x^2 = 8^2
x^2 = 32
area = 32
area of one of the 4 segments = (1/4)(16π-32) = 4π - 8
Step-by-step explanation:
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