Question

a Square ABCD of side 1 m with side AB is horizontal at bottom and CD at top with points A, B, C and D taken in anticlockwise order is subjected to forces of 40N at A, 30N at B ,20N at c, 10 N at D find resultant ​

Answer 1

Answer:

Suppose they meet x hrs after 8 a.m.

then

(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]

= 330

So, 60x+75(x-1) = 330

x=3.

Step-by-step explanation: